[LinuxBIOS] Silly Question
Alan Carvalho de Assis
acassis at gmail.com
Mon Mar 26 15:03:19 CEST 2007
2007/3/26, joe at smittys.pointclark.net <joe at smittys.pointclark.net>:
> This is a silly question but, when I see something like this (2<<20)
> in raminit.c it is saying to change bit 20 to a value of 2?? Is that
> correct?? That would have to be a binary value than right? Than what
> would that look like?? Just trying to understand the whole registry
> setting thing better.
This is a shift operation, then you need think it in binary:
2 = 10 (binary)
10 << 20 = 1000000000000000000000
This operation is just to set the 22th bit.
This is equivalent to 1 << 21.
More info read about shift operation:
> Thanks - Joe
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