Off by eight.

Jordan Archer jarcher at pobox.com
Tue Nov 18 19:59:00 CET 2003


How does the fallback version get executed?  Stepping through the reset 
sequence it looks from my image that that's the default.

Jordan

At 02:52 PM 11/18/2003, ron minnich wrote:
>On Tue, 18 Nov 2003, Jordan Archer wrote:
>
> > I'm pretty sure that it's not 32 bit reset code.  The problem appears if I
> > try to build an image without a fallback.
>
>oh. When I try to build an image without a fallback (this part is
>counterintuitive) I always just build a fallback. Possibly that's the
>wrong thing to do :0)
>
>ron




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