[coreboot] Dump GPIO I/O Registers

[Stefan Reinauer]

Sorry for joining in late. I wrote a utility a while ago that dumped the
GPIO registers of an ICH7. Maybe your registers look pretty similar.

My output is something like:
Intel Southbridge: 8086:27b8
GPIOBASE = 0x0480

gpiobase+0x0000: 0x1f1ff7c0
gpiobase+0x0004: 0xe0e8efc3
gpiobase+0x0008: 0x00000000
gpiobase+0x000c: 0xebffeeff
gpiobase+0x0010: 0x00000000
gpiobase+0x0014: 0x00000000
gpiobase+0x0018: 0x00000000
gpiobase+0x001c: 0x00000000
gpiobase+0x0020: 0x00000000
gpiobase+0x0024: 0x00000000
gpiobase+0x0028: 0x00000000
gpiobase+0x002c: 0x00002180
gpiobase+0x0030: 0x000000ff
gpiobase+0x0034: 0x00000030
gpiobase+0x0038: 0x00010035
gpiobase+0x003c: 0x00000000





* joe at smittys.pointclark.net <joe at smittys.pointclark.net> [080219 10:59]:
> Quoting Peter Stuge <peter at stuge.se>:
> 
> > On Mon, Feb 18, 2008 at 07:45:55PM -0500, joe at smittys.pointclark.net wrote:
> >> > Once you have the base address, you can read the GPIO control
> >> > registers from /dev/port, with the seek equal to the base address.
> >>
> >> How?? This is the part I am looking for, this would be the golden
> >> ticket:-)
> >
> > Oh! This can be fairly simple.
> >
> > dd if=/dev/ioport bs=1 skip=$[0xbasehere] count=asmanyasyouwant | xxd
> >
> >
> OK, so lets clarify?
> 
> GPIOBASE?GPIO Base Address (LPC I/F?D31:F0)
> 31:16 Reserved
> 15:6 Base Address ? R/W. Provides the 64 bytes of I/O space for GPIO.
> 5:1 Reserved
> 0 Resource Indicator ? RO. Hardwired to 1; indicates I/O space.
> 
> 1. My value is 0x00000501. So if only bits 15:6 are the base address  
> this would make my base address 0x14 correct? This value would become  
> "0xbasehere"?
> 
> 2. Would I put 64 in "asmanyasyouwant" to dump the whole 64 bytes of  
> I/O space?
> 
> 3. What is the pipe xxd for?
> 
> Thanks again for the help:-)
> 
> Thanks - Joe
> 
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> 

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